Home
Class 14
MATHS
The centre of a circle passing through t...

The centre of a circle passing through the points (0, 0), (1, 0) and touching the circle `x^(2)+y^(2)=9`, is

A

(3/2, 1/2)

B

(1/2, 3/2)

C

(1/2, 1/2)

D

(1/2, ±2^1/2)

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • SIMPLIFICATION

    RS AGGARWAL|Exercise question|15 Videos

  • SIMPLE INTEREST

    RS AGGARWAL|Exercise All Questions|124 Videos

  • SQUARE ROOTS AND CUBE ROOTS

    RS AGGARWAL|Exercise All Questions|219 Videos

Similar Questions

Explore conceptually related problems

Statement-1: The centre of the circle passing through the points (0, 0), (1, 0) and touching the circle C : x^(2)+y^(2)=9 lies inside the circle. Statement-2: If a circle C_(1) passes through the centre of the circle C_(2) and also touches the circle, the radius of the circle C_(2) is twice the radius of circle C_(1)

The center(s) of the circle(s) passing through the points (0,0) and (1,0) and touching the circle x^(2)+y^(2)=9 is (are) ( a) ((3)/(2),(1)/(2)) (b) ((1)/(2),(3)/(2))(c)((1)/(2),2(1)/(2)) (d) ((1)/(2),-2(1)/(2))

The centre of the circle passing through (0, 0) and (1, 0) and touching the circle x^(2)+y^(2)=9 , is

The centre of a circle passing through (0,0),(1,0) and touching the Circle x^(2)+y^(2)=9 is a a ((1)/(2),sqrt(2)) b.((1)/(2),(3)/(sqrt(2))) c.((3)/(2),(1)/(sqrt(2))) d.((1)/(2),-(1)/(sqrt(2)))

Centre of a circle passing through point (0,1) and touching the curve y=x^2 at (2,4) is

The centre of the circle passing through (0.0) and (1,0) and touching the circle x^(2)+y^(2)=a^(2)is:(A)(1/2,1/2)(B)((1)/(2),-sqrt(2))(C)(3/2,1/2)(D)(1/2,3/2)'