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Determine the osmotic pressure of a solu...

Determine the osmotic pressure of a solution prepared by dissolving 25 mg of `K_(2)SO_(4)` in 2 litre of water at `25^(@)C`, assuming that it is completely dissociated.

Text Solution

Verified by Experts

Osmotic pressure is given by :
`pi =(n//V)RT`, where V is the volume of solution containing n number of moles of solute. Given, weight of solute = 0.25 g and V = 2.0 L
So, `n=0.025 g//174 "g mol"^(-1)`
`=1.43xx10^(-4)`
So, now putting the values:
`pi =(1.43xx10^(-4))/(2)dm^(3)0.0821`
`dm^(3)"atm K"^(-1)"mol"^(-1) xx 298.15`
`=0.018" atm mol"^(-1)`
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