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An element occurs in body centered cubic...

An element occurs in body centered cubic structure. Its density is `8.0 g//cm^(3)`. If the cell edge is 250 pm, calculate the atomic mass of an atom of this element. `(N_(A)=6.023xx10^(23))`

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To calculate the atomic mass of an element that occurs in a body-centered cubic (BCC) structure with a given density and cell edge length, we can follow these steps: ### Step 1: Identify the given values - Density (d) = 8.0 g/cm³ - Cell edge length (a) = 250 pm = 250 × 10⁻¹² m = 250 × 10⁻¹⁰ cm - Number of atoms per unit cell (Z) for BCC = 2 - Avogadro's number (N_A) = 6.023 × 10²³ ...
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