Draw the structures of the following:
`IF_(7)`

Explanation

To draw the structure of IF₇ (Iodine heptafluoride), we will follow these steps:

### Step 1: Determine the Valence Electrons
Iodine (I) has 7 valence electrons, and each fluorine (F) atom has 7 valence electrons. Since there are 7 fluorine atoms, we calculate the total number of valence electrons:
- Iodine: 7 electrons
- Fluorine: 7 electrons × 7 = 49 electrons
- Total = 7 + 49 = 56 valence electrons

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