With reference to the coordination compler ion `[Fe(H_(2)O)_(6)]^(2+)` answer the following: (at. no. of Fe=26)
How many unpaired electrons are there in the complex ion?

Explanation

To determine the number of unpaired electrons in the coordination complex ion \([Fe(H_2O)_6]^{2+}\), we can follow these steps:

### Step 1: Determine the oxidation state of iron in the complex.
The complex ion is \([Fe(H_2O)_6]^{2+}\). Since water (\(H_2O\)) is a neutral ligand, the oxidation state of iron (Fe) can be calculated as follows:

Let the oxidation state of Fe be \(x\).
\[
x + 0 = +2 \quad (\text{since the overall charge of the complex is } +2)
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