If (ax)/costheta+(by)/(sintheta)=a^2-b^2...

If `(ax)/costheta+(by)/(sintheta)=a^2-b^2`and `(axsintheta)/cos^2theta-(bycostheta)/sin^2theta=0`,show that `(ax)^(2//3)+(by)^(2//3)=(a^2-b^2)^(2//3)`

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