Using the energy conservation, derive the expression for the minimum speeds at different locations along a vertical circular motion controlled by gravity. Also prove that the difference between the extreme tensions (or normal forces) depends only upon the weight of the object.

Derive an expression for difference in tensions at highest and lowest point for a particle performing vertical circular motion.

A tiny stone of mass 20 g is tied to a practically massless, inextensible, flexible string and whirled along vertical circles. Speed of the stone is 8 m//s when the centripetal force is exactly equal to the force due to the tension. Calculate minimum and maximum kinetic energies of the stone during the entire circle. Let theta= 0^0 be the angular position of the string, when the stone is at the lowermost position. Determine the angular position of the string when the force due to tension is numerically equal to weight of the stone. Take g = 10 m//s^2 and Length string = 1.8 m

A particle of mass1kg, tied to a 1.2 m long string is whirled to perform vertical circular motion, under gravity. Minimum speed of a particle is 5 m//s . Consider following statements. (P) Maximum speed must be 5sqrt5 m//s . (Q) Difference between maximum and minimum tensions along the string is 60 N. Which of the following is true?

A particle of mass 1 kg, tied to a 1.2 m long string is whirled to perform vertical circular motion, under gravity. Minium speed of a particle is 5 m/s. Consider the following statements . P) Maximum speed must be root (5) (5) m/s Q) Difference between maximum and minimum tensions along the string is 60 N.