M.i of the solid sphere about its diameter is 25 kg m^2`. Find its M.I about the tangent.

If moment of inertia of a solid sphere of mass 5 kg about its diameter is 50 kg m^2 . Its moment of inertia about its tangent in kg m^2 is

M.I.of a uniform disc about an axis passing through its centre and perpendicular to its plane is 10 kg m^2 .Find its M.I. about the diameter.

Moment of inertia of a solid sphere about its diameter is I. If that sphere is recast into 8 identical. Small spheres, then moment of inertia of each such small sphere about its diameter is

A solid sphere has a radius R . If the radius of gyration of this sphere about its diameter is sqrt(2//5) R , show that the radius of gyration about the tangential axis of rotation is sqrt(7//5) R

The moment of inertia of a solid sphere of mass M and radius R, about its diameter is (2//5) MR^2 . Its M.I. about parallel axis passing through a point at a distance (R//2) from its centre is

If the moment of inertia of a ring about transverse axis passing through its centre is 6 kg m^2 , then the M.I. about a tangent in its plane will be

The moment of inertia of a ring about one of its diameters is 2 kg m^2 . What will be its moment of inertia about a tangent parallel to the diameter ?

The M.I. of solid sphere of mass M and radius R about its diameter is

A circular disc of radius R and thickness R/6 has moment of inertia I about an axis passing through. Its is melted and recast into a solid sphere. What is the moment of inertia of the solid sphere about its diameter as the axis of rotation?

If the moment of inertia of a thin uniform circular disc about diameter „is I, then its M.I. about an axis perpendicular to its plane and passing through a point on its rim will be