A drop of mercury of radius 0.2 cm is broken into 8 droplets of the same size. Find the work done if the surface tensions of mercury is 435.5 dyne/cm

A drop of mercury of radius 0.2 cm is broken into 8 droplets of the same size. Find the work done if the surface tension of mercury is 435.5 dyne/cm.

If a drop of water of radius 0.1 cm is broken up into a million droplets all of the same size, then the energy expand in the process will be (T=75 dyne//cm)

If a mercury drop of radius 1 cm is sprayed into 10^6 droplets of equal size, then the energy absorbed in joules will be. (Surface tension of mercury is 460xx10^-3 N//m)

Calculate the work done in breaking a mercury drop of radius 1mm into one thousand droplets of the same size. Surface tension of mercury is 525 xx 10^-3 N//m .

Eight droplets of mercury each of radius 1 mm coalesces into a single drop. Find the change in the surface energy. Surface tension of mercury is 0.465 J//m^2

A spherical drop of oil of radius 1 cm is broken into 1000 droplets of equal radii. If the surface tension of oil is 50 dyne/cm, the work done is

If a mercury drop of radius 1 cm is broken into a million of equal size, then the work done will be (T=35xx10^-2N//m)

Find the surface area of a sphere of radius 3.5 cm.

A liquid drop of radius R is broken up into n small droplet. The work done is proportional to