A steel ball with radius 0.3mm is falling with velocity of `2 m//s` at a time t, through a tube filled with glycerin, having coefficient of viscosity `0.833 Ns//m^2`. Determine viscous force acting on the steel ball at that time.

Spherical balls of radius 'r' are falling in a viscous fluid of viscosity eta with a velocity 'v' .The retarding viscous force acting on the spherical ball is

Spherical balls of radius 'R' are falling in a viscous fluid of viscosity 'eta' with a velocity 'v'. The retarding viscous force acting on the spherical ball is

Calculate the viscous force acting on a rain drop of diameter 1mm, falling with a uniform velocity 2 m//s through air. The coefficient of viscosity of air is 1.8 xx 10^-5 Ns//m^2 .

A small steel ball of mass m and radius r is falling under gravity through a viscous liquid of coefficient of viscosity eta . If g is the value of acceleration due to gravity. Then the terminal velocity of the ball is proportional to (ignore buoyancy)

Find the terminal velocity of a steel ball bearing of radius 0.1cm when it falls through a tube filled with glycerine. ( rho_(steel) = 8 g//cm^3 , a = 1.34 g//cm^3 , r| = 9 poise)

A rain drop of radius 0.5 mm has a terminal velocity in air 2 m/s. If the coefficient of viscosity of air is 1.8xx10^(-4) poise, the viscous drag on the rain drop will be

The terminal velocity of a water drop of radius 0.01 mm falling through air is 1.12 cm/s. If the density of air is neglected, the coefficient of viscosity of air is [density of water =10^(3) kg//m^(3), g=9.8m//s^(2)]

Two metal ball of radius R and 2 R falling through a fluid have same velocity at some point. The viscous drag acting on them at that instant are in the ratio

Calculate the force required to move a flat metal plate of area 25cm^2 with a uniform velocity of 20 m//s over the surface of a liquid 1 mm thick if the coefficient of viscosity (n) is 2 Ns//m^2