What should be the diameter of a soap bubble , in order that the excess pressure inside it is `51.2 N/m^2` ?

What should be the diameter of a water drop so that the excess pressure inside it is 80N/m^2 ?

What should be the diameter of a water drop so that the excess pressure inside it is 80 N//m^2 ? (surface tension of water = 7.2 xx 10^-2 N//m )

The excess pressure inside a bubble is

If the volumes of two soap bubbles are V and 8V then ratio of the excess pressures inside those bubbles is

Two soap bubbles have radii in the ratio of 2:1 The ratio of the excess pressures inside them is

The bubbles have radii in the ratio 3:4 . The ratio of excess pressure inside them is

The ratio of excess pressure inside a soap bubble to the excess pressure inside an air bubble in a soap solution is

The excess pressure inside a soap bubble is twice the excess pressurre inside a second soap bubble. The volume of the first bubble is n times the volume of the second where n is

A bubble of radius 10 cm is formed with a solution that has surface tension 40xx10^-3 N//m . What is the excess pressure inside the bubble in N//m^2 ?