Twenty seven droplets of water , each of radius 1.1 mm coalesce into a single drop .Find the change in surface energy. Surface tension of water is 0.072 N/m.

Twenty seven droplets of water, each of radius 0.1 mm coalesce into a single drop. Find the change in surface energy. Surface tension of water is 0.072 N//m .

Eight droplets of water, each of radius 0.2 mm, coalesce into a single drop . Find the change in total surface energy. (Surface tension of water = 0.072 N/m)

Eight droplets of mercury each of radius 1 mm coalesces into a single drop. Find the change in the surface energy. Surface tension of mercury is 0.465 J//m^2

Eight droplets of water each of radius 0.5 mm, when coalesce into single drop, then the change in surface energy will be,

Two mercury drops each of radius r merge to form a bigger drop. Calculate the surface energy released.

1000 droplets of water having 2 mm diameter each coalesce to form a single drop . Given the surface tension of water is 0.072 Nm^(-1) .the energy loss in the process is

The radius of a soap bubble is reduced from 5 cm to 1 cm. Then the change in surface energy of the bubble is.(T=0.02 N/m)

n droplets of equal size of radius r coalesce to form a bigger drop of radius R. The energy liberated is equal to