What should be the diameter of a water drop so that the excess pressure inside it is `80N/m^2` ?

What should be the diameter of a water drop so that the excess pressure inside it is 80 N//m^2 ? (surface tension of water = 7.2 xx 10^-2 N//m )

What should be the diameter of a soap bubble , in order that the excess pressure inside it is 51.2 N/m^2 ?

The excess pressure inside a bubble is

Two soap bubbles have radii in the ratio of 2:1 The ratio of the excess pressures inside them is

The bubbles have radii in the ratio 3:4 . The ratio of excess pressure inside them is

Derive an expression for excess pressure inside a liquid drop.

A bubble of radius 10 cm is formed with a solution that has surface tension 40xx10^-3 N//m . What is the excess pressure inside the bubble in N//m^2 ?

If the surface tension of a soap water is 0.04 N//m . Then the excess pressure inside a 10 mm diameter soap bubble in N//m^2 will be

Explain excess of pressure inside a liquid drop.