A spherical oil drop falls at a steady rate of 2 cm/s in still air. Find diameter of the drop . Take g =980 cm/s^2`. The coefficient of viscosity of air is `1.8 xx 10^(-4)` Poise, Density of oil = 0.8 gm/ cm^3` , Density of air = 1 gm/ cm^3`

A spherical drop of oil falls at a constant speed of 4 cm//s in steady air. Calculate the radius of the drop. The density of the oil is 0.9 g//cm^3 , density of air is 1.0 g//cm^3 and the coefficient of viscosity of air is 1.8 xx 10^-4poise , ( g = 980 cm//s^2 )

A rain drop of radius 0.5 mm has a terminal velocity in air 2 m/s. If the coefficient of viscosity of air is 1.8xx10^(-4) poise, the viscous drag on the rain drop will be

Calculate the viscous force acting on a rain drop of diameter 1mm, falling with a uniform velocity 2 m//s through air. The coefficient of viscosity of air is 1.8 xx 10^-5 Ns//m^2 .

The terminal velocity of a water drop of radius 0.01 mm falling through air is 1.12 cm/s. If the density of air is neglected, the coefficient of viscosity of air is [density of water =10^(3) kg//m^(3), g=9.8m//s^(2)]

Energy density of wire is 0.25 J//m^(3), when its extension is 0.2 cm. Find density of wire, when elongation is 1 cm

What will be the approximate terminal velocity of a rain drop of diamteter 1.8xx 10^(-3)m, when density of rain water ~~10^(3)kgm^(-3) and the co-efficient of viscosity of air ~~1.8xx10^(-5)Nsm^(-2) ? (Neglect buoyancy of air. )

The water flows form a tap of diameter 1.25 cm with a rate of 5xx10^(-5) m^(3) s^(-1). The density and coefficient of viscosity of water are 10^(3)kg m ^(-3) and 10^(-3) Pa. s respectively. The flow of water is

The velocity of sound in air at 0^@C is [rho=1.29 kg m^(-3) lambda=1.36 , density of mercury= 13000 kg//m^3 , g=9.8 m//s^2] .