0.5 mole of gas at temperature 300 K expands isothermally from an initial volume of 2.0L to final volume of 6.0L. What is the work done by the gas ? `(R = 8.31 J mol^(-1) K^-(1)`

0.5 mole of gas at temperature 300 K expands isothermally from an initial volume of 2.0L to final volume of 6.1L. How much heat is supplied to the gas?.

Three moles of an ideal gas kept at a constant temperature of 300 K are compressed from a volume of 4 litre to 1 litre. Calculate the work done in the process. (R = 8.31 J mol^-1 K^-1 )

One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 litre to 10 litre. The DeltaU for this process is (R = 2 cal K^-1 mol^-1) .

A gas is allowed to expand in a well insulated container against a constant extremal pressure of 2.5 bar from an initial volume of 2.5 L to a final volume of 4.5L.The change in internal energy. DeltaU of the gas will be

Three moles of an ideal gas are expanded isothermally from a volume of 300cm^3 to 2.5L at 300 K against a pressure of 1.9 atm. Calculate the work done in L atm and joules

2 moles of an ideal gas are expanded isothermally and reversibly from 20 L to 30 L at 300K. Calculate the work done (R = 8.314 JK^(-1) mol^(-1))

A gas expands in volume from 2 L to 5 L against a pressure of1atm at constant temperature. The work done by the gas will be