A reversible engine converts one fifth of heat which it absorbs from source into work. When the temperature of the sink is reduced by `70^@` , its efficiency is doubled. Calculate the temperature of the source and the sink .

An engine has an efficiency of 1/6 . When the temperature of sink is reduced by 62^(@)C , its efficiency is doubled. Temperature of the source is

A reversible engine converts one third input into work. When the temperature of the sink is reduced by 62 °C, then efficiency of the engine is tripled. The temperature of the source and sink are

If the absolute temperatures of the source and sink of a heat engine are in the ratio 4 : 3 , its efficiency is

A Carnot engine has the same efficiency between 100 k and 500 k .Calculate the temperature T K & 900 K of the sink.

The efficiency of a Carnot cycle is 1/6 . If on reducing the temperature of the sink by 65^@C , the efficiency becomes 1/3 , find the initial and final temperatures between which the cycle is working.

A Carnot engine, whose efficiency is 40% , takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60% . Then, the intake temperature for the same exhaust (sink) temperature must be:

When the absolute temperature of the source of a Carnot heat engine is increased by 25 %, its efficiency increases by 80%. The new efficiency of the engine is

Heat engine takes 300 cal of heat 500 K and rejects 150 cal of heat to sink. The temperature of sink is

If two thirds of the heat taken by a heat engine from the source is given to the sink, its efficiency is

An ideal heat engine working between temperature T_(1) and T_(2) has an efficiency eta , the new efficiency if both the source and sink temperature are doubled, will be