Calculate the least amount of work that must be done to freeze one gram of water at ` 0 ^@ C` by means of the refrigerator.The temperature of the surrounding is ` 27 ^@ C`.How much heat is passed on the surrounding in this process? Latent heat of fusion L=80 cal/g.

Calculate the heat absorbed if the initial temperature of 50g ice is 0^@C to change into water of the same temperature (Latent heat of fusion of ice is 80 cal//g )

Calculate the amount of heat required to convert 80 g of ice at 0⁰C into water at the same temperature . (Specific latent heat of fusion of ice = 80 cal/g)

Calculate the amount of heat absorbed by 100 g of ice to change into water of 30^@ C.(Latent heat of fusion of ice is 80 cal//g )

Find the heat required to convert 20 g of ice at 0⁰C into water at the same temperature . (Specific latent heat of fusion of ice = 80 cal/g)

Calculate the amount of heat absorbed by 500 g of ice to change into water of 20^@C . (specific heat capacity of water is 1 cal//g^@C )

How many calories of heat will be absorbed when 2kg of ice at 0⁰C melts ? (Specific latent heat of fusion of ice = 80 cal/g)

30 gm of ice at 0^@C is placed in a calorimeter of mass 20 gm also at 0^@C . 100 gm of water at 90^@C is poured into the calorimeter. Find the final temperature. (specific heat of calorimeter = 0.4 cal//gm ^@C , Specific heat of water = 0.42 cal//gm ^@C Latent heat of fusion of ice = 80calg )

Calculate the quantity of heat released during the conversion of 10g of ice cold water (temperature 0⁰C ) into ice at the same temperature. (Specific latent heat of fusion of ice = 80 cal/g)

Heat absorbed when 1 g of ice melts at 0^@C to form 1 g of water at the same temperature is ______cal

1 of a steam at 100^@C melts how much ice at 0^@C ? ( Latent heat of ice=80 cal/g and latent heat of steam =540 cal/g )