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If an average person jogs, he proiduces ...

If an average person jogs, he proiduces `14.5 xx 10^3 cal min^-1`. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires `580 xx 10^3cal` for evaporationa) is

A

`0.25 kg`

B

`2.35 kg`

C

`0.05 kg`

D

`0.20 kg`

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