Home
Class 12
PHYSICS
If particle executing S.H.M. has an ampl...

If particle executing S.H.M. has an amplitude of 6 cm, its acceleration at a distance 2 cm from mean position is `8 cm/s^2`, then the maximum speed of the particle will be

A

`8 cm/s`

B

`12 cm/s`

C

`16 cm/s`

D

`24 cm/s`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

A particle executing simple harmonic motion has an amplitude of 6 cm . Its acceleration at a distance of 2 cm from the mean position is 8 cm/s^(2) The maximum speed of the particle is

A particle is executing a linear S.H.M. Its velocity at a distance x from the mean position is given by v^2=144-9x^2 . The maximum velocity of the particle is

A particle executing S.H.M. starts from the mean position. Its phase, when it reaches the extreme position, is

The kinetic energy of a particle executing S.H.M. is 16 J when it is at its mean position. If the mass of the particle is 0.32 kg , then what is the maximum velocity of the particle

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the acceleration of the particle at a distance 5 cm from the equilibrium position.

A particle executing SHM has a maximum speed of 30 cm s ^-1 and a maximum acceleration of 60 cm s ^-2 . The period of oscillation is

The acceleration of a particle executing S.H.M, when it is at its mean position is

A particle executes simple harmonic motion with an amplitude of 4 cm . At the mean position the velocity of the particle is 10 cm/ s . The distance of the particle from the mean position when its speed becomes 5 cm/s is

A particle executes linear simple harmonic motion with an amplitude of 3 cm . When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the velocity of the particle at a distance 5 cm from the equilibrium position.