A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the velocity of the particle at a distance 5 cm from the equilibrium position.

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the acceleration of the particle at a distance 5 cm from the equilibrium position.

The P.E. of a particle executing SHM at a distance x from its equilibrium position is

A particle is executing S.H.M. of amplitude 5 cm and period of 2 s. Find the speed of the particle at a point where its acceleration is half of its maximum value.

A particle executes S.H.M. with an amplitude 0.5 m and frequency 100 Hz. The maximum speed of the particle will be

A particle executes SHM with amplitude of 20 cm and time period of 12 s. What is the minimum time required for it to move between two points 10 cm on either side of the mean position?

A particle executes S.H.M. with a period 8 s . Find the time in which half the total energy is potential.

A particle executes simple harmonic motion with an amplitude of 4 cm . At the mean position the velocity of the particle is 10 cm/ s . The distance of the particle from the mean position when its speed becomes 5 cm/s is

Assertion: Total energy of a particle executing S.H.M. · is maximum at mean position . Reason: The velocity of the particle executing S.H.M. is maximum at mean position.

A particle of mass m executing S.H.M. about its mean position. The total energy of the particle at given instant is

A particle of mass 200 gm, performs S.H.M ofamplitude 0.1 m and period 3.14 sec.. Its PE when it is at a distance of 0.03 m from the mean position is