A body of mass `100 gm` is suspended from a light spring which stretches it by 10 cm. Find the force constant of the spring.

A spring has a natural length of 50 cm and a force constant 2 xx 10^3N/m . A body of mass 10 kg is suspended from it and the spring is stretched . If the body is pulled down further stretching the string to a length of 58 cm and released, it executes simple harmonic motion. The force on the body when it is at its lowermost position of oscillation will be

Maximum kinetic energy of a particle suspended from a spring in oscillating state is 5 joule and amplitude is 10 cm. The force constant of the spring will be

The period of oscillation of a body of mass m_1 suspended from a lightspring is T. When the body of mass m_2 , is tied to the first body and the system is made to oscillate, the period is 2T. Compare the masses m_1 and m_2 .

A body of mass 50 kg is suspended using a spring balance inside a lift at rest. If the lift starts falling freely, the reading of the spring balance is

One-forth length of a spring of force constant K is cut away. The force constant of the remaining spring will be

A mass M is suspended from a massless spring. An additional mass m stretches the spring further by a distance x . The combined mass will oscillate with a period

A mass is suspended from a vertica spring which is executing SHM of frequency 5 Hz. The spring is unstretched at the highest point of oscillation. Maximum speed of the mass is (take, acceleration due to gravity, g=10m//s^(2) )

Choose the correct options A mass of 10 kg is suspended from a rope wound on a wheel of diameter 40 cm. The torque about the axis of rotation is

A metal block of mass 10 kg is kept on a table. If the contact surface area is 100 cm^2 . Find the pressure on the table.