The maximum velocity and maximum acceleration of a particle in linear S.H.M. is `0.21m/s` and `0.84 m/s^2` respectively . Find its period.

The acceleration of a particle in S.H.M. is

In S.H.M. maximum acceleration is a

Graph between velocity and displacement of a particle, executing S.H.M. is

The maximum velocity of a particle in S.H.M. is 0.16 mis and maximum acceleration is 0.64 m/ s^2 . The amplitude is

The maximum speed of a particle performing linear S.H.M is 0.08 m/s .If its maximum acceleration is 0.32 m/s^2 , calculate its period

The maximum velocity and the maximum acceleration of a body moving in a simple harmonic oscillator are 2 m/s and 4 m//s^(2) . Then angular velocity will be

The maximum speed of a particle performing linear S.H.M is 0.08 m/s .If its maximum acceleration is 0.32 m/s^2 , calculate its amplitude.

The maximum velocity of a particle performing a linear S.H.M is 0.16 frac(m)(s) , if its maximum acceleration is 0.64 (m)(s^2) it period is

The speeds of a particle performing linear S.H.M. are 8 cm/s and 6 cm/s at respective displacements of 6 cm and 8 cm . Find its period and amplitude.