A particle is executing S.H.M. of amplitude 5 cm and period of 2 s. Find the speed of the particle at a point where its acceleration is half of its maximum value.

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the velocity of the particle at a distance 5 cm from the equilibrium position.

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the acceleration of the particle at a distance 5 cm from the equilibrium position.

A particle executes S.H.M. with an amplitude 0.5 m and frequency 100 Hz. The maximum speed of the particle will be

A particle of mass m executing S.H.M. about its mean position. The total energy of the particle at given instant is

A particle executing SHMpassing through the mean position with a velocity of 4 ms^-1 . The velocity of the particle at a point where the displacement is half of the amplitude is

A particle executes S.H.M. with a period 8 s . Find the time in which half the total energy is potential.

Assertion: Total energy of a particle executing S.H.M. · is maximum at mean position . Reason: The velocity of the particle executing S.H.M. is maximum at mean position.

A particle is performing linear S.H.M of amplitude a. What fraction of the total energy is kinetic, given the displacement is half the amplitude

A particle performs linear S.H.M. starting from the mean position. Its amplitude is A and time period is T. At the instance when its speed is half the maximum speed , its displacement x is

Acceleration of a particle, executing SHM, at it’s mean position is