A particle executes S.H.M. with a period `8 s`. Find the time in which half the total energy is potential.

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the acceleration of the particle at a distance 5 cm from the equilibrium position.

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the velocity of the particle at a distance 5 cm from the equilibrium position.

The potential energy of a particle executing S.H.M. is 2.5 J, when its displacement is half of amplitude. The total energy of the particle will be

A particle is executing S.H.M. of amplitude 5 cm and period of 2 s. Find the speed of the particle at a point where its acceleration is half of its maximum value.

A particle executes SHM with a time period of 8 s . If it starts from the extreme position at time t = 0 , the ratio of distance covered by it in 1st and 2nd seconds is

A particle of mass 0.5 kg executes SHM. If its period of oscillation is pi seconds and total energy is 0.04 J , then the amplitude of oscillation will be

A particle executes S.H.M. of period 12 second and amplitude 8 cm. What time will it take to travel 4 cm from the extreme position and what will be the velocity at that instant ?

A particle executes S.H.M. with an amplitude 0.5 m and frequency 100 Hz. The maximum speed of the particle will be

A particle is executing S.H.M. along a straight line. The graph showing the variation of kinetic, potential and total energy K, U and T respectively with displacement is -

A particle performs S.H.M. of period 4 seconds and amplitude 4 cm. If initially the particle is at positive extremity, how much time will it take to cover a distance of 1 cm from the extreme position?