A bob a simple pendulum performs S.H.M. of amplitude 2 cm. If the mass of the bob is 100 gram and its total energy is `32 xx 10^-5 J`. Find the periodic time of S.H.M.

In a S.H.M., the path length is 4 cm and the maximum acceleration is 2pi^(2) cm//s^(2) . The periodic time of S.H.M. is

When the displacement in S.H.M is one third of the amplitude, the fraction of the potential energy to total energy is

A particle of mass 0.2 kg moves with simple harmonic motion of amplitude 2 cm. If the total energy of the particle is 4 xx10^(-5) J, then the time period of the motion is

At what distance, is the KE of a particle, performing S.H.M of amplitude 10 cms is three times its PE

An object performing S.H.M. with mass of 0.5 kg force constant 10 N/m and amplitude 3 cm what is the total energy of object ?

A simple pendulum performs S.H.M of period 4 seconds. How much time after crossing the mean position , will the displacement of the bob be one third of its amplitude.

A particle is performing linear S.H.M of amplitude a. What fraction of the total energy is kinetic, given the displacement is half the amplitude

A particle performs S.H.M of amplitude 10 cm. Its maximum velocity during oscillations is 100 (cm)(s) What isits displacement, when the velocity is 60 (cm)(s) .