A particle executes S.H.M. of period 12 second and amplitude 8 cm. What time will it take to travel 4 cm from the extreme position and what will be the velocity at that instant ?

A particle performs S.H.M. of period 12 second and amplitude 8 cm. If initially the particle is at the position extremity , how much time will it take to cover a distance of 6 cm from the extreme position ?

A particle executes linear simple harmonic motion with an amplitude of 2 cm . When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A particle executes linear simple harmonic motion with an amplitude of 3 cm . When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is

A particle performs S.H.M. of period 4 seconds and amplitude 4 cm. If initially the particle is at positive extremity, how much time will it take to cover a distance of 1 cm from the extreme position?

A particle executes S.H.M. with a period 8 s . Find the time in which half the total energy is potential.

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the velocity of the particle at a distance 5 cm from the equilibrium position.

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the acceleration of the particle at a distance 5 cm from the equilibrium position.

A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . The shortest time it takes to reach a point a/sqrt2 from its mean position in seconds is

If particle executing S.H.M. has an amplitude of 6 cm, its acceleration at a distance 2 cm from mean position is 8 cm/s^2 , then the maximum speed of the particle will be