A particle executing S.H.M. has velocities `v_1` and `v_2` when at distances `x_1` and `x_2` from the centre of the path. Show that the time period given by

A particle is executing SHM along a straight line. Its velocities at distances x_(1) and x_(2) from the mean position are v_(1) and v_(2) , respectively. Its time period is

Derive expression for final velocities v_1 and v_2 for an Elastic collsion.

A particle executing S.H.M. starts from the mean position. Its phase, when it reaches the extreme position, is

The kinetic energy of a particle executing S.H.M. is 16 J when it is at its mean position. If the mass of the particle is 0.32 kg , then what is the maximum velocity of the particle

A particle is executing a linear S.H.M. Its velocity at a distance x from the mean position is given by v^2=144-9x^2 . The maximum velocity of the particle is

If particle executing S.H.M. has an amplitude of 6 cm, its acceleration at a distance 2 cm from mean position is 8 cm/s^2 , then the maximum speed of the particle will be

The time period of a particle executing S.H.M. is 1 s. If the particle starts motion from the mean position, then the time during which it will be at mid way between mean and extreme position will be

The acceleration of a particle performing a linear S.H.M. is 16 cm//s^(2) , when it is at a distance of 4 cm from the mean position. The period of S.H.M. is

A particle is executing S.H.M. of amplitude 5 cm and period of 2 s. Find the speed of the particle at a point where its acceleration is half of its maximum value.

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the velocity of the particle at a distance 5 cm from the equilibrium position.