The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m. If the piston moves with simple harmonic motion with an angular frequency of `200 rad min ^-1`, what is its maximum speed ?

An object performing S.H.M. with mass of 0.5 kg force constant 10 N/m and amplitude 3 cm what is its maximum speed ?

The equation of a damped simple harmonic motion is m(d^2x)/(dt^2)+b(dx)/(dt)+kx=0 . Then the angular frequency of oscillation is

Two simple harmonic motion of angular frequency 100and 1000 rads^(-1) have the same displacement amplitude The ratio of their maximum acceleration is

A body is executing simple harmonic motion with an angular frequency 2 rad/ s . The velocity of the body at 20 mm displacement, when the amplitude of motion is 60 mm , is

A particle executes simple harmonic motion of amplitude A. (i) At what distance from the mean positio is its kinetic energy equal to its potential energy? (ii) At what points is its speed half the maximum speed?

A particle of mass 0.2 kg moves with simple harmonic motion of amplitude 2 cm. If the total energy of the particle is 4 xx10^(-5) J, then the time period of the motion is

A body of mass 1 is executing simple harmonic motion. Its displacement y(cm) at t seconds is given by y = 6 sin (100t + pi//4) . Its maximum kinetic energy is

A particle executes linear simple harmonic motion with an amplitude of 2 cm . When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A particle executing simple harmonic motion has an amplitude of 6 cm . Its acceleration at a distance of 2 cm from the mean position is 8 cm/s^(2) The maximum speed of the particle is

If at any time, the displacement of a simple pendulum be 0.02 m, then its acceleration is 2 m/ s^2 . What is the angular speed of the pendulum at that instant?