The length of second 's pendulum on the surface of earth is nearly 1 m . Its length on the surface of moon should be [ Given : acceleration due to gravity (g) on moon is `1/6th` of that on the earth 's surface]

The length of a second's pendulum on the surface of earth is 1 m. What will be the length of a second's pendulum on the moon?

The acceleration due to gravity on the surface of earth varies

The mass and weight of an object on the earth are 5 kg nad 49 N respectively. What will be their values on the moon ? Assume that the acceleration due to gravity on the moon is 1/6th of that on the earth.

Solve the following examples / numerical problems: The mass and weight of an object on the earth are 5 kg and 49 N respectively. What will be their values on the moon? Assume that the acceleration due to gravity on the moon is 1/6th of that on the earth.

As we go above the earth's surface , the value of acceleration due to gravity increases.

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

A body is taken to a height of nR from the surface of the earth . The ratio of acceleration due to gravity on the surface to that at the altitude is

If a body is taken from the surface of earth to moon, then its weight will

Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth

The gravitational force on the surface of th Moon is _______ times than that on the surface of the Earth.