Find the displacement of a simple harmonic oscillator at which its P.E. is half of the maximum energy of the oscillator.

In a simple harmonic oscillator, at the mean position

The displacement of a simple harmonic oscillator is x = 5 sin (pi t /3) m . Then its velocity at t =1 s , is

Show that motion of a damped harmonic oscillator is S.H.M. Hence derive the formula for time period of damped oscillations.

The velocity-time diagram of a harmonic oscillator is shown in the adjoining figure . The frequency of oscillation is

As shown in figure, a simple harmonic motion oscillator having identical four springs has time period

The total energy of a simple harmonic oscillator is 3xx10^(-5) J and maximum force acting on the body is 1.5xx10^(-3) N. If the period of the motion is 2s and initial phase is 30^(@) , then the equation of motion will be

When the potential energy of a particle executing simple harmonic motion is one-fourth of its maximum value during the oscillation, the displacement of the particle from the equilibrium position in terms of its amplitude a is

Which of the following is not a simple harmonic motion?

A particle starts performing simple harmonic motion. Its amplitude is A . At one time its speed is half that of the maximum speed. At this moment the displacement is

The maximum velocity and the maximum acceleration of a body moving in a simple harmonic oscillator are 2 m/s and 4 m//s^(2) . Then angular velocity will be