n organ pipe open at both ends vibrate with a frequency 'n' which is its `p^th` overtone. When one end of the pipe is closed , it vibrate with a frequency N which is its `q ^th` overtone, show that `N =(2q +1) n / 2 (p+1)`

A pipe open at both ends gives frequencies which are

A pipe open at both the ends has a fundamental frequency of 600 Hz . The first overtone of a pipe closed at one end has the same frequency as the first overtone of the open pipe. How long are the two pipes ?

A tube open at both ends has fundamental frequency 'n'. If one end of the tube is dipped in water to half of its length , what would be the fundamental frequency ?

Length of an organ pipe open at both ends in 33.3 cm. If velocity of sound is 333 m/s.,then the frequency of fifth overtone is

An organ pipe P_(1) closed at one end vibrating in its first overtone and another pipe P_(2) open at both ends vibrating in third overtone are in resonance with a given tuning fork . The ratio of the length of P_(1) to that of P_(2) is

An organ pipe closed at one end has fundamental frequency of 500 Hz . The maximum number of overtones generated by this pipe which a normal person can hear is

A taut string at both ends viberates in its n^(th) overtone. The distance between adjacent Node and Antinode is found to be 'd'. If the length of the string is L, then

The difference between the frequencies of the first and second overtones of an air column closed at one end is 280 Hz. Find the frequency of its third overtone.

If pipe open at both the ends has an effective length of 0.5 m, then the frequency of the note which is octave its fundamental frequency will be