A sonometer wire of length 50 cm is stretched by keeping weights equivalent of 3.5 kg. The fundamental frequency of vibration is `125 Hz`. Determine the linear density of the wire ?

A sonometer wire of length 0.5 m is stretched by a weight of 5 kg. The fundamental frequency of vibration is 100 Hz . Determine the linear density of material of wire.

A sonometer wire of length 1.5m is made of steel. The tension in it produces an elastic strain of 1% . What is the fundamental frequency of steel if density and elasticity of steel are 7.7 xx 10^(3) kg//m^(3) and 2.2 xx 10^(11) N//m^(2) respectively ?

A wire of length 0.5 m is stretched by a weight of 2 kg. If the mass per unit length of the wire is 1.96 xx 10^-3 kg//m , find the fundamental frequency of the wire and the frequency of its first overtone

Sonometer wire is kept under tension of 2kg wt . If resonating length of the wire is 18 cm in fundamental mode of vibration , find the frequency of vibration of the wire. (Linear density of the wire = 0.008 gram /cm, g = 9.8 m/s^2 )

A uniform wire under tension , is fixed at its ends. If the ratio of tension in the wire to the square of its length is 360 dyne /cm^2 and fundamental frequency of vibration of wire is 300Hz , find its linear density.

The length and diameter of a metal wire is doubled the fundamental frequency of vibration will change from n to (tension being kept constant and material of both the wires is same)

Two wires of the same material and same cross section are stretched on a sonometer. One wire is loaded with 1.5 kg and another is loaded with 6 kg. The vibrating length of first wire is 60 cm and its fundamental frequency of vibration is the same as that of the second wire. Calculate vibrating length of the other wire.