Calculate the distance of the fifth dark band from the central bright band in a biprism experiment .(Given `lambda` = `6000 overset (@)(A)` , distance between the virtual images of the slit = 1.2 mm and distance between source and screen = 100 cm .)

Calculate the distance of the 30th bright band in a biprism experiment , if the distance of the 15th bright band, from the centre of the interference pattern is 6 mm.

In biprism experiment the distance between the two virtual images of the slit is 0.1 cm and the distance between the slit and biprism is 1 m .If the band width is 0.058 cm , calculate the wavelength of light .

In a biprism experiment, the distance between the slit and screen is 1 m and distance between the images of the slit is 0.274 mm. If the fringewidth is 0.2 cm, the wavelength of light is

In a biprism experiment , the distance between the slit and the focal plane of the eyepiece is 1.2 m and the wavelength of light used is 5000 overset (@)(A) . When a convex lens is interposed (between the biprism and eyepiece) the images of the slits in the two positions are 5 mm and 1.8 mm apart . The distance between the centre of the pattern and twelfth dark band is

In a biprism experiment, the fringes are observed in the focal plane of the eye piece at a distance of 1.2m from the slits. The distance between the central bright band and 20th bright band is 0.4 cm. When a convex lens is placed between biprism and the eyepiece, the distance between the two vertical magnified images is found to be 0.9 cm. Determine the wavelength of light used.

In an experiment with Fresnel biprism sodium light is used and bands 0.0196 cm in width are observed at the distance of 100 cm from the slit. A convex lens is placed between the biprism and the slit. If the distance between the slit and screen is one meter, the magnified distance apart of the images is found to be 0.7 cms, the lens being 30 cm from the slit, calculate the wavelength of light.

Describe how the distance between the two virtual sources in the biprism experiment is measured. Derive the necessary formula.

In a biprism experiment , the slit is illuminated by a light of wavelength of 5000 overset (@)(A) . The distance between the slit and eyepiece is 1 m . If the distance between the two virtual sources is 0.25 cm , then distance between fifth bright band on one side and the sixth dark band on the other sideof the central bright band will be

Following observations were made in a biprism experiment. Distance between virtual images of slit = 5 mm. Distance between slit and eyepiece = 75 cm. Distance between second dark band and tenth dark band of same side of centre is 0.576 mm. Calculate wavelength of light used.