Describe how the distance between the two virtual sources in the biprism experiment is measured. Derive the necessary formula.

If the distance between the observer and source decresase with time, then it show that

In a biprism experiement, the slit is illuminated by light of wavelength 4800 overset@A . The distance from the slit to the screen is 1 metre. If the distance between the two virtual sources is 0.3 cm, determine the distance between the 5th bright band on one side and 5th dark band on the other side.

If the distance between the observer and source decreases with time, then it shows that

In biprism experiment the distance between the two virtual images of the slit is 0.1 cm and the distance between the slit and biprism is 1 m .If the band width is 0.058 cm , calculate the wavelength of light .

In a biprism experiment , the slit is illuminated by a light of wavelength of 5000 overset (@)(A) . The distance between the slit and eyepiece is 1 m . If the distance between the two virtual sources is 0.25 cm , then distance between fifth bright band on one side and the sixth dark band on the other sideof the central bright band will be

Explain how a moving coil Galvanometer is converted into an ammeter. Derive the necessary formula.

Explain how a moving coil galvanometer is converted into voltmeter. Derive the necessary formula.

The distance between two successive particles which differ in phase by

In a biprism experiment , the distance between the virtual images of the slits is 2.5 mm and the eyepiece is at a distance of 1 m from the slits . If the fringe width is 0.3 mm then the frequency of source of light is

Describe with the help of neat diagram how will you determine the internal resistance of a cell by using potentiometer. Derive the necessary formula.