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A slab of material of dielectric constan...

A slab of material of dielectric constant k has the same area A as the plates of a parallel plate capacitor and has thickness `(3d//4)`, where d is separation of the plates.The charge in capacitance when the slab is inserted between the plates is

A

`C = (A epsilon_0)/d [(k + 3)/(4k)]`

B

`C = (A epsilon_0)/d [(2k)/(k + 3)]`

C

`C = (A epsilon_0)/d [(k + 3)/(2k)]`

D

`C = (A epsilon_0/d [(4k)/(k + 3)]`

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