A parallel plate air condenser has a capacity of `21 mu F` . What will be the new capacity if
A marble slab of dielectric constant 8 is introduced between the two plates?

A parallel plate air condenser has a capacity of 20 mu F . What will be the new capacity if the distance between two plates is doubled ?

The capacity of a parallel plate condenser with dielectric constant 10 is 12 mu F . What will be its capacity if dielectric is removed ?

A parallel plate condenser with air as dielectric has capacity C_0 = (in_0 A)/(d) . A thin mica sheet of dielectric constant K and thickness is introduce near the first plate and then moved with constant velocity v towards the other plate . The capacity of the condenser will be

A parallel plate air capacitor has a capacitance of 3 xx 10^-9F . A slab of dielectric constant 3 and thickness 3cm completely fills the space between the plates. The potential difference between the plates is maintained constant at 400 volt. What is the change in the energy of capacitor if the slab is removed?

A parallel plate air capacitor has a capacitance of 4muF . A slab of dielectric constant 4 and thickness 4 cm completely fills the space between the plates. The potential difference between the plates is maintained constant at 200 volt. What is the change in the energy of a capacitor if the slab is removed?

The capacity of a parallel plate air condenser is 8 muF . When air is replaced by another material, its capacity becomes 16muF . Calculate the dielectric constant of other material.

A charged parallel plate capacitor has a potential energy U. if a slab of dielectric constant k is inserted between the plates, then the new potential energy will be_

A parallel plate capacitor with air between the plates has a capacitance of 8 pF.What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constants 6 ?