What is the area of the plates of a 2 F parallel plate capacitor,given that the separation between the plates is 0.5 cm ?

To reduce the capacity of a parallel plate condenser,separation between the plates is

A slab of material of dielectric constant k has the same area A as the plates of a parallel plate capacitor and has thickness (3d//4) , where d is separation of the plates.The charge in capacitance when the slab is inserted between the plates is

On what factors does the capacitance of a parallel plate capacitor depend ?

Explain in brief, the parallel plate capacitor.

Derive an expression for capacitance of a parallel plate capacitor without a dielectric slab between the plates.

A p.d.of 200 volt ismaintained acrosstwo parallel plates of a parallel plate capacitor. Distance between the two platesis 4 mm.Calculate electric field intensity between the two plates

In a parallel plate capacitor with air between the plates, each plate has an area of 6 xx 10^-3 m^2 and the separation between the plates is 2 mm. If this capacitor is connected to 100 V supply , what would be the charge on each plate ?

In a parallel plate capacitor with air between the plates, each plate has an area of 6 xx 10^-3 m^2 and the separation between the plates is 2 mm. How would charge on the plates be affected if a 2 mm thick mica sheet of k = 6 is inserted between the plates while the voltage supply remains connected ?