Home
Class 12
PHYSICS
The current,in a potentiometer wire of 1...

The current,in a potentiometer wire of 100 cm length, is adjusted to give a null point at 50 cm with a standard cell of e.m.f.1.018 V.The e.m.f.of a cell which gives null point at 60 cm is

A

1.221 V

B

2.22 V

C

3.22 V

D

4.22 V

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

In figure,the potentiometer wire A B has a resistance of 5 Omega and length 10m. The balancing length AJ for the cell of e.m.f.of 0.4 V is

A potentiometer wire of length 100 cm has a resistance of 10Omega . It is connected in series with a resistance and an accumulator of e.m.f. 2 V and negligible internal resistance. A source of e.m.f. 10 mV is balanced against a 40 cm length of the potentiometer wire. The value of the external resistance is

A potentiometer wire is 10 meter long and a potential difference of 6 volt is maintained between its ends. Find the e.m.f. of a cell which balances a length of 180 cm of the potentiometer wire.

In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm length of the wire. If cell is replaced by another cell and the balance point shifts to 63.0 cm, what is the emf of the second cell?

Describe how potentiometer is used to compare the e.m.f.s of two cells by combination method.

A cell of e.m.f. 2 V and negligible internal resistance is connected in series with a potentiometer wire of length 100 cm. The e.m.f of the Leclanche cell is found to balance on 75 cm of the potentiometer wire. The e.m.f. of the cell is

In given figure, the potentiometer wire AB has a resistance of 5Omega and length 10 m. The balancing length AM for the e.m.f. of 0.4 V is

A potentiometer wire has a length of 2m and resistance 10Omega . It is connected in series with resistance 990Omega and a cell of emf 2V. Calculate the potential gradient along the wire.

A potentiometer wire of length 4 m and resistance 8 Omega is connected in, series with a battery of e.m.f. 2 V and negligible internal resistance. If the e.m.f. of cell balances against length of 217 cm of the wire, find the e.m.f. of cell. When the cell is shunted by assistance of 15 Omega ,the balancing length is reduced to 200 cm. Find the internal resistance of the cell

Two cells having unknown emfs E_1 and E_2 (E_1 > E_2) are connected in potentiometer circuit so as to assist each other. The null point is obtained at 8.125m from higher potential end. When cell E_2 is connected so as to oppose cell E_1 , the null point is obtained at 1.25m from the same end compare the emfs of two cells.