Write relationship between e.m.f. of a cell and its internal resistance.

A Cell sends a current of 0.5 A through a 2 Omega resistance. If the resistance is increased by 5 Omega , the current falls to 0.25 A. Find the emf of the cell and its internal resistance.

Write the relationship between lake and birds on tree?

Choose correct alternative. The emf of a cell of negligible internal resistance is 2 V. It is connected to the series combination of 2 Omega , 3 Omega and 5 Omega resistances. The potential difference across 3 Omega resistance will be (in volt)

A circuit consists of two cells, each of e.m.f. E and internal resistances r_(1) and r_(2) are connected in series through an external resistance X. If the potential difference between the ends of the first cell is zero, the value of X in terms of r_(1) and r_(2) will be

A lead resistance R is connected across a cell of emf E and internal resistance r. If the closed circuit p.d. across the terminals of the cell is V the internal resistance of the cell is.

In potentiometer experiment, if l_1 is the balancing length for emf of cell of internal resistance r and l_2 is the balancing length for its terminal potential difference when shunted with resistance R then

An alternating e.m.f. is applied to purely capacitive circuit. The phase relation between e.m.f. and current flowing in the circuit is

In a potentiometer experiment it is found that no current passes through the galvanometer when the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is shunted by a resistance of 5Omega balance is obtained when the cell connected across 0.4m of the wire. Find the internal resistance of the cell.

Obtain a relationship between density of a subtances and edge length of unit cell.

A potentiometer wire of length 10 m and resistance 9 ohm is connected to a battery of e.m.f. 2.1 volt having internal resistance 1.5 Omega . Find the potential gradient along the wire and the balancing length for a cell of e.m.f. 1.08 volt .