A potential drop per unit length along a wire is `5 xx 10^-3 V//m`. If the emf of a cell balances against length 216 cm of this potentiometer wire, find the emf of the cell.

A potentiometer wire of length 4 m and resistance 8 Omega is connected in, series with a battery of e.m.f. 2 V and negligible internal resistance. If the e.m.f. of cell balances against length of 217 cm of the wire, find the e.m.f. of cell. When the cell is shunted by assistance of 15 Omega ,the balancing length is reduced to 200 cm. Find the internal resistance of the cell

A potentiometer wire of length 10 m is connected in series with a battery the emf of a cell balances against 250 cm length of wire if length of potentiometer wire is increased by 1 m then new balancing length of wire will be

The resistance per unit length of a wire is 1Omega//"m" . A Leclanche cell of e.m.f. 1.45 V is balanced against 2.9 m length of potentiometer wire. The current through the wire is

A potentiometer wire is 10 meter long and a potential difference of 6 volt is maintained between its ends. Find the e.m.f. of a cell which balances a length of 180 cm of the potentiometer wire.

A cell of e.m.f. 2 V and negligible internal resistance is connected in series with a potentiometer wire of length 100 cm. The e.m.f of the Leclanche cell is found to balance on 75 cm of the potentiometer wire. The e.m.f. of the cell is

In an experiment to determine the internal resistance of a cell of emf 1.5 V, the balance point in the open cell condition is 76.3 cm. When a resistor of 9.5 ohm is used in the external circuit of the cell the balance point shifts to 64.8 cm of the potentiometer wire. Determine the internal resistance of the cell.

A potentiometer wire has a resistance per unit length of 0.1 Omega//m . A cell of emf 1.5V balance against 300 cm length of the wire. Find the current through potentiometer wire.

In a potentiometer experiment, e.m.f. of a cell is balanced by a length of 150 cm on the potentiometer wire. When the cell is shunted by a 10 Omega resistance, the balancing length reduces to 90 cm. What is the internal resistance of the cell?

A potentiometer wire of length 100 cm has a resistance of 10Omega . It is connected in series with a resistance and an accumulator of e.m.f. 2 V and negligible internal resistance. A source of e.m.f. 10 mV is balanced against a 40 cm length of the potentiometer wire. The value of the external resistance is