A current of 3 A flows through certain resistance when a cell is connected across it.The potential difference across the resistance was found to be 4.8 volt. The e.m.f.of cell is 5 volt.Calculate the internal resistance of the cell.

A lead resistance R is connected across a cell of emf E and internal resistance r. If the closed circuit p.d. across the terminals of the cell is V the internal resistance of the cell is.

A current of 150 mA flows through a wire when the potential difference between its ends is 300 volt. Calculate the resistance of the wire,

Why there is no way to separate the internal resistance from the e.m.f. of a cell?

Write relationship between e.m.f. of a cell and its internal resistance.

Does the value of resistance of a conductor depend upon the potential difference applied across it or current passed through it?

Choose correct alternative. emf of a cell is 2.2 volt. When resistance R = 5 Omega is connected in series potential drop across the cell becomes 1.8 volt. Value of internal resistance of the cell is

When a resister of 10Omega is connected across a cell, its terminal potential difference is balanced by 150cm of potentiometer wire and when 20Omega resistance is connected across the cell, terminal potential difference is balanced by 175cm of the same potentiometer wire. Find the balancing length when the cell is in open circuit and also find the internal resistance of the cell.

A cell of emf 1.1 V and internal resistance r is connected across as external resister of resistance 10r. Find the potential difference across the external resistor.

In a potentiometer experiment, it is found that no current passes through the galvanometer when the terminals of the cell are connected across 52 cm of the potentiometer wire. If the cell is shunted by a resistance of 5 Omega the balance point is found at 40 cm of the wire from the same end. The internal resistance of the cell is

When a resistor of 5 Omega resistance is connected across a cell,its terminal potential difference is balanced by 150 cm of the wire and when a resistor of 10 Omega resistance is connected across cell, the terminal p.d. is balanced by 175 cm of same potentiometer wire. Find the balancing length when the cell is in open circuit and the internal resistance of acell.