Two resistance x and y in the two gaps of a meter bridge give a null point dividing the wire in the ratio `2:3`. If each resistance is increased by `30Omega`,the null point divides the wire in the ratio `5:6`. calculate each resistance.

With resistances P and Q in the left and the right gap respectively of a metre bridge, the null point divides the wire in the ratio 3:4 . When P andQ are increased by 20 Omega each,the null point divides the wire in the ratio 5:6 . The values of P and Q are

With resistances P and Q in the left and right gaps of a metre bridge, the balance point divides the wire in the rati 1/3. When P and Q are increased by 40Omega , the balance point divides the wire in the ratio 3/5. The values of P and Q will be respectively

Resistance in the two gaps of a meter bridge are 10 ohm and 30 ohm respectively. If the resistances are interchanged he balance point shifts by

With a resistance R_1 in the left gap and a resistance R_2 in the right gap of a meterbridge, the null point is obtained at a distance of 70cm from the left end, when R_1 is reduced by 2Omega and R_2 is increased by 2Omega , the null point is obtained at 30cm from left end. Find the values of resistance R_1 and R_2 .

Two equal resistances are introduced in two gaps of a metre bridge.Find the shift in the null point if an equal resistance is connected in series with resistance in left gap .

With an unknown resistance X in the left gap and a resistance of 30 Omega in the right gap of meter bridge . The null point is obtained at 40 cm from the left end of the wire . Find i) the unknown resistance and ii)the shift in the position of the null point , when the resistance in each gap is shunted by a resistance of 8 Omega .

With an unknown resistance X in the left gap and a resistance of 30 Omega in the right gap of meter bridge . The null point is obtained at 40 cm from the left end of the wire . Find i) the unknown resistance and ii)the shift in the position of the null point , when the resistances in both the gaps are increased by 15 Omega .

In an experiment of meter bridge, a null point is obtaining at the center of the bridge wire. When a resistance of 10 ohm is connected in one gap, the value of resistance other gap is

Two resistances are connected in the two gaps of a meter bridge. The balance point is 20 cm from the zero end. When a resistance 15 Omega is connected in series with the smaller of two resistance, the null point+ shifts to 40 cm . The smaller of the two resistance has the value.

Two wires have lengths in the ratio 1:4 and radii in the ratio 1: 2 . The resistivities of the materials of the wires are in the ratio 5: 1 . Compare their resistances.