The resistance of a galvanometer is `4052 Omega`. What shunt must be connected so that 1% of the total current will flow through the galvanometer?

A galvanometer has a resistance of 3663Omega . A shunt Sis connected across it such that (1/34) of the total current passes through the galvanometer. Then the value of the shunt is :

We have a galvanometer of resistance 25 Omega . It is shunted by a 2.5 Omega wire. The part of total current that flows through the galvanometer is given as

If a galvanometer is shunted by one third of its resistance, find the fraction of total current passing through the galvanometer.

A 36 Omega galvanometer is shunted by resistance of 4Omega . The percentage of the total current, which passes through the galvanometer is

Resistance of a bulb is 500 Omega . It is connected to a battery of potential difference 220 V. How much current will flow through it?

Resistances are connected in …..so as to pass the same current through them.

What is the value of the shunt resistance that allows 20% of the main current through a galvanometer of 99 Omega ?.

A resistance of 2Omega is connected in parallel to a galvanometer of resistance 48Omega . Find the percentage of fraction of total current passing through the resistance of 2Omega .

If galvanometer is shunted by (1/n)^ th resistance, then the the fraction of current passing through the galvanometer will be