Equal lengths of magnin `(p_1)` and nichrome `(p_2)` are joined in the left hand and right hand gaps of meter-bridge.The null point is 40 cm from the left end. Compare the diameters of the wire. The specific resistances are `p_1 = 4.8 xx 10^-8 Omega m, p_2=10^-6 Omega m`.

The unknown resistance is placed in a left gap and a resistance of 50 Omega in right gap of meter bridge. The null point is obtained at 60 cm from the right gap. Determine the unknown resistance.

With an unknown resistance X in the left gap and a resistance of 30 Omega in the right gap of meter bridge . The null point is obtained at 40 cm from the left end of the wire . Find i) the unknown resistance and ii)the shift in the position of the null point , when the resistance in each gap is shunted by a resistance of 8 Omega .

With an unknown resistance X in the left gap and a resistance of 30 Omega in the right gap of meter bridge . The null point is obtained at 40 cm from the left end of the wire . Find i) the unknown resistance and ii)the shift in the position of the null point , when the resistances in both the gaps are increased by 15 Omega .

Two resistances X Omega and Y Omega are connected in the left and right gap of a metre bridge. A null point was found on the bridge wire such that the ratio of lengths of two segments of wire is 2:3 . The distance of the null point was measured from the left end of the wire. When the valueof X is increased by 20 Omega , the position of the null point divides the wire into segments of lengths in the ratio 4:1 .Determine X and Y.

Two unknown resistances are connected in two gaps of a meter-bridge. The null point is obtained at 40 cm from left end. A 30Omega resistance is connected in series with the smaller of the two resistances, the null point shifts by 20 cm to the right end. The value of smaller resistance in Omega is

The resistance of a 1m long nichrome wire is 6 Omega . If we reduce the length of the wire to 70 cm, what will its resistance be?

Two resistances are connected in the two gaps of a meter bridge. The balance point is 20 cm from the zero end. When a resistance 15 Omega is connected in series with the smaller of two resistance, the null point+ shifts to 40 cm . The smaller of the two resistance has the value.

Calculate the specific resistance of the material of a wire having a resistance of 4.4 Omega , length 1.1 m and radius 0.2 mm.

With resistances P and Q in the left and the right gap respectively of a metre bridge, the null point divides the wire in the ratio 3:4 . When P andQ are increased by 20 Omega each,the null point divides the wire in the ratio 5:6 . The values of P and Q are

With resistances P and Q in the left and right gaps of a metre bridge, the balance point divides the wire in the rati 1/3. When P and Q are increased by 40Omega , the balance point divides the wire in the ratio 3/5. The values of P and Q will be respectively