An alternating e.m.f. is given by 100 sin `100 pi `t to a pure resistance of` 50 Omega`. calculate:-frequency

An alternating e.m.f. is given by 100 sin 100 pi t to a pure resistance of 50 Omega . calculate:- r.m.s current through the circuit.

An alternating e.m.f. is given by 100 sin 100 pi t o a pure resistance of 50 Omega . calculate:- peak value of e.m.f

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:-frequency

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:-peak value of e.m.f.

An alternating e.m.f., e = 300 sin 100 pi t volt, is applied to a pure resistance of 100 Omega . The r.m.s. current through the cicuit is

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:-r.m.s. current through the circuit

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:- power dissipated in the circuit.

A alternating e.m.f. e = 200 sin (100 pit) is connected across a resistor of resistance 10 Omega . Calculate the r.m.s. current flowing through the circuit.

An alternating voltage given by e=140 sin 3142t is connected across a pure resistor of 50Omega .Find:- the frequency of the source