Calculate the self-inductance of a coaxial cable of length l and carrying a current I.The current flows down the inner cylinder with radius a, and flows out of the outer cylinder with radius b.

A coil of length L, carries a current i. The magnetic moment of coil is proportional to

The magnetic force acting on a conductor of length l carrying a current I placed in field of strength B is given as

A wire of length L carrying a current I is bent into a circle. The magnitude of the magnetic field at the centre of the circle is

A wire of length l, carrying current i, is bent in circle of radius r, then magnetic moment at centre of loop is

A conductor of length '1' and carrying current "I" kept in uniform magnetic field "B" experiences a force.

The magnetic moment of a current carrying loop whose circumference with radius 'r' is equal to the perimeter of square with length / is

Magnetic induction produced at the centre of a circular loop carrying current is B . The magnetic moment of the loop of radius R is

If L denotes the inductance of an inductor through which a current i is flowing, the dimensions of Li^(2) are

The magnetic field at the centre of a circular coil of radius r carrying current l is B_(1) . The field at the centre of another coil of radius 2r carrying same current l is B_(2) . The ratio (B_(1))/(B_(2)) is

Calculate the magnitude of the magnetic induction due to a circular coil of 400 turns and radius 0.05 cm, carrying a current of 5A, at a point on the axis of the coil at a distance of 0.1 m from the centre of the coil.