A device Y is connected across an AC source of emf e =`e_osinomegat`.the current through y is given as i =`i _osin(omegat+(pi/2))`:-Draw the phasor diagram for the device Y.

A device Y is connected across an AC source of emf e = e_osinomegat .the current through y is given as i = i _osin(omegat+(pi/2)) :-How doesthe reactance of the device Y vary with the frequency of the AC? Show graphically.

A device Y is connected across an AC source of emf e = e_osinomegat .the current through y is given as i = i _osin(omegat+(pi/2)) :-Draw graphs showinh variation of emf and current with time over one cycle of AC for Y.

A device Y is connected across an AC source of emf e = e_osinomegat .the current through y is given as i = i _osin(omegat+(pi/2)) :-Identify the device Y and write the expression for its reactance.

A capacitor of 2 muF is connected to an AC source of emf e = 250 sin 100 pit . Write an equation for instantaneous current through the circuit and give reading of AC ammeter connected in the circuit.

An alternating voltage given by e=140 sin 3142t is connected across a pure resistor of 50 Omega .Find:- the rms current through the resistor.

Select and write the most appropriate answer. The instantaneous current in an A.C. circuit is given by I = 2 sin (omegat +theta) ampere. The r.m.s. value of the current is

An inductance of 0.5 H,a capacitor of capacitance 10^-9 F and a resistance of 100 Omega are connected in series across A.C. source of e.m.f. 10 V.The current through the circuit at resonance is

The slope of the tangent at (x , y) to a curve passing through (1,pi/4) is given by y/x-cos^2(y/x), then the equation of the curve is