If the intensity of incident radiation in a photocell is increased, how does the stopping potential vary?

As the intensity of incident light increases

When the intensity of light incident on a photodiode increases, how is the reverse current affected?

Assertion: If the intensity of incident radiation on a metal is doubled, then K.E. of photoelectrons emitted will be doubled. Reason: K.E.=1/2mv^2=h(v-v_0), where v is the velocity of photo electrons.

Increase in the frequency of the incident radiations increases the

In a photocell frequency of incident radiation is increased by keeping other factors constant (vgtv_(0)) , the stopping potential