If intensity of radiation falling on metal surface is doubled, what happens to K.E. of electron emitted?

Assertion: If the intensity of incident radiation on a metal is doubled, then K.E. of photoelectrons emitted will be doubled. Reason: K.E.=1/2mv^2=h(v-v_0), where v is the velocity of photo electrons.

On reducing the intensity of radiation falling on the surface of a material, the

The frequency of incident light falling on a photosensitive metal plate is doubled, the K.E of the emitted photo-electrons is

When light of 2.5 eV falls on a metal surface, maximum kinetic energy of electron is T. If incident radiation of 4 eV falls on same metal surface, maximum kinetic energy of electrons is doubled. The work function of metal is

The wavelength corresponding to the threshold frequency for a certain metal is 5000overset@ A. Calculate the Max. K.E. of the photoelectron emitted when ultraviolet light of wavelength 2500overset@A falls on it.