An electron and an alpha particle have the same kinetic energy. How are the de-Broglie wavelengths associated with them related?

A proton , a neutron , an electron and an alpha -particle have same energy. Then their de Broglie wavelengths compare as

The kinetic energy of an electron is 500 eV. Calculate the de-Broglie wavelength associated with it.

A proton and an alpha-particle are accelerated,using the same potential difference. How are the de Broglie wavelengths lambda_P and lambda_alpha related to each other?

An electron, a proton, α -particle and a hydrogen atom are moving with the same kinetic energy. The associated de-Broglie wavelength will be longest for

An electron, a proton, an alpha-particle and a hydrogen atom are moving with the same kinetic energy.The associated de Broglie wavelength will be longest for

When the kinetic energy of an electron is increased, the wavelength of the associated wave will

A proton and an alpha-particle are accelerated through the same potential difference. The ratio of the de Broglie wavelength of the proton to the de Broglie wavelength of the alpha-particle will be

The de Broglie wavelength (lambda) associated with a material particle is_____.

A proton and electron have same K.E.Which one has greater de-Broglie wavelength and why?